홀 전류 센서 -WCS1800, 아날로그 전압 출력
(Hall Current Sensor -WCS1800, Analog Output)
개요
- 본 제품은 홀 전류 센서 -WCS1800, 아날로그 전압 출력입니다.
- 전류 측정센서로 측정된 전류에 따라 아날로그 전압 출력을 내보내는 제품입니다.
- 보드의 포텐셔미터를 이용하여 전류 threshold 값을 설정하면, 설정된 전류값보다 센싱된 값이 클시 디지털 출력을 HIGH로 출력하는 기능도 갖고 있습니다.
- 이 경우 LED가 켜지게 됩니다.
- DC: ± 35A; AC: 25A 의 전류값 센싱이 가능합니다.
- 센서는 DC5V로 동작합니다.
특징
- 1, The working voltage: DC5V
2, The current detection range: DC: ± 35A; AC: 25A (for analog output);
3, Linearity: K = 60mV / A;
4, Limit current range: 0.5A - 35A (for the switch output);
5, With over-current signal indicator;
6, With mounting holes, easy to install on you device;
7, The sampling current convert to analog voltage signal output, can be connected to ADC; TTL level signal output, can be connected to the microcontroller’s I/O .
8, The output signal is: analog voltage signal and switch signal.
9, Board size: 37*31mm - Interface description:
VCC: positive power supply;
DOUT: TTL high / low level switch signal output;
GND: power supply negative;
AOUT: analog voltage signal.
문서
- Click to download document
-
Analog Voltage Signal Output (AOUT) Using Introduction:
Relationship between detection current and analog signal output is shown as below:
Analog Signal Output: V0=Vcc*0.5la*K (Ia is actual current through current detection pin, and K is linearity )
For example input current is 1A , Vcc=5V, and WCS1800 linearity is 60mV/A.
Lets simply explain the corresponding relationship between WCS1800 detection current and output voltage:
1).When the current flows into from positive direction:
Formula: V0=Vcc*0.5+ Ia*K
Corresponding output: V0=(2.5+0.06)V=2.56V
2).When the current flows into from negative direction:
Formula: V0=Vcc*0.5- Ia*K
Corresponding output V0=(2.5-0.06)V=2.44V
.If it is AC signal:
V0=Vcc*0.5+ Ia*K
Corresponding output range: 2.44V-2.56V
Above are ideal values, and there might be some little precision error.